But I know, sometimes you just want to memorize a mathematical formula and plug numbers in. If that's what you're looking for, then this is just for you. Heat capacity problems can pretty much all be solved using the formula:

(Energy transferred) = (Heat capacity) x (Amount of substance) x [(Final temperature) - (Initial temperature)]

Or, if we want to make that shorter:
E = (C

Let's plug in information from 2 different problems:_{p}) x (g) x (T_{final}- T_{initial})1. A 250.0g sample of water (C

_{p}= 1

^{calorie}/

_{(g)(°C)}) is heated from 14.3°C to 27.4°C. How many calories of heat energy have been transferred?

Plugging in to the formula:

E = (1

^{calorie}/_{(g)(°C)}) (250.0g) (27.4°C - 14.3°C) = 3275calories2. A 400.0g sample of water is initially at 16.8°C. If 5000 calories of energy is added to the water, what is the final temperature?

Plugging in again:

5000 calories = (1

Same thing, but now we have to do a little algebra to solve for T^{calorie}/_{(g)(°C)}) (400.0g) (T_{final}- 16.8°C)_{final}, and we get a final temperature of 29.3°C.

If you prefer a more descriptive solution to heat capacity problems, take a look at http://scienceofcooking100.blogspot.com/2015/11/heat-capacity.html

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